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∞ sort filezilla server log entries by session id
#!/bin/bash # # entry example # # (1579051) 10/16/2009 0:02:13 AM - (not logged in) (192.168.1.11)> USER chris # # sort -k1n fzs-2009-10-16.log # does not work properly because when the session id and timestamp are the same # it goes on and tries to sort based on the message # if the timestamp granularity was high enough it would work (and so much faster!) # [ $# -ne 1 ] && echo "number of args required is 1" && exit 1 [ ! -e $1 ] && echo "file $1 does not exist" && exit 2 FILEPATH=`dirname $1` LOGNAME=`basename $1` LOGNAME_SORTED=${FILEPATH}/${LOGNAME}".sorted" SID_SORTED_FILENAME=${FILEPATH}/"fzlog_sid_sorted.$$" rm -f $LOGNAME_SORTED awk '{ split( $1, L, "\\(|\\)" ); print L[ 2 ]; }' $1 | sort | uniq > ${SID_SORTED_FILENAME} cat ${SID_SORTED_FILENAME} | while read line do grep "^($line)" $1 >> ${LOGNAME_SORTED} done rm -f ${SID_SORTED_FILENAME} exit 0



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